document.write( "Question 208248: A quality control expert is called in to determine whether a newly installed machine is producing a particular cotton cloth according to the specifications set by the manufacturer. The mean warp-breaking strength of this particular cotton cloth has been established to be 66 pounds. \r
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document.write( "A random sample of 36 pieces of cotton cloth is obtained from a production run on this machine. The results of the sample reveal a mean warp-breaking strength of 64.5 pounds and a standard deviation of 5 pounds. Can the quality control expert say that the cotton produced on the new machine meets the warp-breaking specification of the manufacturer at the .05 level of significance? \n" );
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Algebra.Com's Answer #159896 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A quality control expert is called in to determine whether a newly installed machine is producing a particular cotton cloth according to the specifications set by the manufacturer. The mean warp-breaking strength of this particular cotton cloth has been established to be 66 pounds. \n" ); document.write( "A random sample of 36 pieces of cotton cloth is obtained from a production run on this machine. The results of the sample reveal a mean warp-breaking strength of 64.5 pounds and a standard deviation of 5 pounds. Can the quality control expert say that the cotton produced on the new machine meets the warp-breaking specification of the manufacturer at the .05 level of significance? \n" ); document.write( "-------------------------------------------------------------------------- \n" ); document.write( "Ho: u = 0.66 \n" ); document.write( "Ha: u >= 66 \n" ); document.write( "---------------------- \n" ); document.write( "sample mean = 64.5 \n" ); document.write( "alpha = 5% on a right-tail test. \n" ); document.write( "----------- \n" ); document.write( "I ran a 1-sample T-test and got the following results: \n" ); document.write( "--- \n" ); document.write( "test statistic = -1.8 \n" ); document.write( "--- \n" ); document.write( "p-value = 0.96 \n" ); document.write( "======================== \n" ); document.write( "Conclusion: Since the p-value is greater than 5% do not reject Ho. \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |