document.write( "Question 211555This question is from textbook Beginning & Intermediate Algebra
\n" ); document.write( ": Find the dimensions of a rectangle whose width is 7 miles less than half its length and whose area is 160 square inches. \n" ); document.write( "

Algebra.Com's Answer #159858 by checkley77(12844) $\"\"$ $\"About$

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LW=AREA
\n" ); document.write( "W=L/2-7
\n" ); document.write( "L(L/2-7)=160
\n" ); document.write( "L^2/2-7L=160
\n" ); document.write( "(L^2-14L)/2=160
\n" ); document.write( "L^2-14L=160*2
\n" ); document.write( "L^2-14L=320
\n" ); document.write( "L^2-14L-320=0
\n" ); document.write( " $\"L+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "L=(14+-SQRT[-14^2-4*1*-320])/2*1
\n" ); document.write( "L=(14+-SQRT[196+1280])/2
\n" ); document.write( "L=(14+-SQRT[1476)/2
\n" ); document.write( "L=(14+-38.42)/2
\n" ); document.write( "L=(14+38.42)/2
\n" ); document.write( "L=52.42/2
\n" ); document.write( "L=26.21 ANS.
\n" ); document.write( "W=26.21/2-7
\n" ); document.write( "W=13.105-7
\n" ); document.write( "W=6.105 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "26.21*6.105=160
\n" ); document.write( "160~160 \n" ); document.write( "

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