document.write( "Question 211529: How many grams of silver that is 60% pure must be mixed together with silver that is 35% pure to obtain a mixture of 90 grams of silver that is 45% pure? \n" ); document.write( "
Algebra.Com's Answer #159852 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! 60%=x=36 gr \n" ); document.write( "35%=90-x=54 gr \n" ); document.write( ".6x+.35(90-x)=.45*90 \n" ); document.write( ".6x+31.5-.35x=40.5 \n" ); document.write( ".25x=9 \n" ); document.write( "x=36 \n" ); document.write( " |