document.write( "Question 211557: the equation |x| = -a where A is a positive interger, what can be said about the solution? how would you modify the value of A so that you would have a solution to |x| = -a of +- a? \n" ); document.write( "
Algebra.Com's Answer #159848 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
There is no solution to \"abs%28x%29=-a\" where \"a%3E0\" since \"abs%28x%29\" is ALWAYS nonnegative (ie not negative).\r
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\n" ); document.write( "\n" ); document.write( "In order to make \"abs%28x%29=-a\" have the solutions of \"x=-a\" or \"x=a\", you need to force 'a' to be negative. So \"abs%28x%29=-a\" has the solutions of \"x=-a\" or \"x=a\" when \"a%3C0\".\r
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\n" ); document.write( "\n" ); document.write( "Ex: \"abs%28x%29=-%28-5%29\" has the solutions \"x=-%28-5%29\" and \"x=-5\". If you plug in either solution, you get\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28-%28-5%29%29=-%28-5%29\" ---> \"abs%285%29=5\" ---> \"5=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28-5%29=-%28-5%29\" ---> \"abs%28-5%29=5\" ---> \"5=5\"
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