document.write( "Question 211479This question is from textbook Beginning & Intermediate Algebra
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document.write( ": An object is thrown upward from the top of an 80 foot building with an initial velocity of 64 feet per second. The height h of an object after t seconds is given by the quadratic equation (((h=-16t^2+64t+80))). When will the object hit the ground. \n" );
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Algebra.Com's Answer #159818 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The problem gives you: \n" ); document.write( "h=-16t^2+64t+80 \n" ); document.write( "where \n" ); document.write( "h is height in feet \n" ); document.write( "t is time in secs \n" ); document.write( ". \n" ); document.write( "If it hits the ground, h = 0 so \n" ); document.write( "set h=0 and solve for t: \n" ); document.write( "h=-16t^2+64t+80 \n" ); document.write( "0=-16t^2+64t+80 \n" ); document.write( "0=-4t^2+16t+5 \n" ); document.write( "Solving using the quadratic equation yields: \n" ); document.write( "t = {-0.29, 4.29} \n" ); document.write( "We can throw out the negative solution leaving \n" ); document.write( "t = 4.29 seconds \n" ); document.write( ". \n" ); document.write( "Details of quadratic to follow: \n" ); document.write( "
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