document.write( "Question 211465This question is from textbook Beginning & Intermediate Algebra
\n" );
document.write( ": The length of a rectangle is 7 centimeters less than twice its width. Its area is 30 square centimeters. Find the dimension of the rectangle. \n" );
document.write( "
Algebra.Com's Answer #159815 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Area = Length * Width \n" ); document.write( ". \n" ); document.write( "but L= 2w-7 \n" ); document.write( ". \n" ); document.write( "A= (2w-7)*w = 2w^2 -7w also = 30,,,,,given \n" ); document.write( ". \n" ); document.write( "2w^2 -7w -30 =0 \n" ); document.write( ". \n" ); document.write( "solve using quadratic formula \n" ); document.write( ". \n" ); document.write( "a=2,,,b=-7,,,,,c=-30 \n" ); document.write( ". \n" ); document.write( "w=[-(-7) +/- sqrt{(-7)^2-4(2)(-30)}]/2(2) \n" ); document.write( ". \n" ); document.write( "w= [ 7 +/- sqrt{49+240}]/4 \n" ); document.write( ". \n" ); document.write( "w= [ 7 +/-sqrt {289}]/4 \n" ); document.write( ". \n" ); document.write( "w= [7 +/- 17]/4 \n" ); document.write( ". \n" ); document.write( "w= 6, -2.5 (not reasonable) \n" ); document.write( ". \n" ); document.write( "l=2w-7 = 2*6-7 = 5 \n" ); document.write( ". \n" ); document.write( "check, A=5*6 =30,,,,,,ok\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |