document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211463>Question 211463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factoring\r<BR>\n" );
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document.write( "4x^2 + 19xy + 12y^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159813 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x^2 +19xy +12y^2<BR>\n" );
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document.write( "sign  of  3rd  term  is  (+) therefore  both  factors  have  same  sign<BR>\n" );
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document.write( "sign  of  second  term  is  (+) ,,,therefore both  factors  are  (+)<BR>\n" );
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document.write( "factors  of  1st  term  are,,  1*4,,2*2<BR>\n" );
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document.write( "Factors  of  3rd  term  are, 1*12,,2*6,,3*4,,<BR>\n" );
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document.write( "Seeking  a  combination  whose  factors  add  to  19<BR>\n" );
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document.write( "Try,,,4*4 + 1*3 = 16+3 = 19<BR>\n" );
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document.write( "(4x +3y)(1x +4y)<BR>\n" );
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document.write( " </SPAN>\n" );
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