document.write( "Question 211368: If the complement of an angle is 5° less than one-sixth of its supplement, find the measure of the angle. \n" ); document.write( "

Algebra.Com's Answer #159807 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the angle be A, its complement is (90-A) and its supplement is (180-A), then:
\n" ); document.write( " $\"90-A+=+%281%2F6%29%28180-A%29-5\"$ Simplify and solve for A. Add 5 to both sides.
\n" ); document.write( " $\"95-A+=+%281%2F6%29%28180-A%29\"$ Multiply both sides by 6.
\n" ); document.write( " $\"570-6A+=+180-A\"$ Add 6A to both sides.
\n" ); document.write( " $\"570+=+180%2B5A\"$ Subtract 180 from both sides.
\n" ); document.write( " $\"390+=+5A\"$ Divide both sides by 5.
\n" ); document.write( " $\"78+=+A\"$
\n" ); document.write( "The angle is 78 degrees. \n" ); document.write( "

\n" );