document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211375>Question 211375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> give exact and approximate solutions to three decimal places for <BR>\n" );
document.write( "y^2-12y+36=100 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159742 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This happens to be a Quadratic Equation that FACTORS!  There are TWO ways to solve it.  I'm not sure which way you want to solve it.\r<BR>\n" );
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document.write( "First, you can factor the left side of the equation and take the square root of each side:<BR>\n" );
document.write( "y^2-12y + 36=100<BR>\n" );
document.write( "(y-6)^2 = 100<BR>\n" );
document.write( "y-6 = +10 or - 10\r<BR>\n" );
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document.write( "y-6=10<BR>\n" );
document.write( "y=16\r<BR>\n" );
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document.write( "y-6=-10<BR>\n" );
document.write( "y-6+6=-10+6=-4\r<BR>\n" );
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document.write( "The other way is to set the equation equal to zero, like this:\r<BR>\n" );
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document.write( "y^2-12y+36-100=0<BR>\n" );
document.write( "y^2 -12y -64 =0\r<BR>\n" );
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document.write( "This just happens to factor also (but it doesn't ALWAYS work this way!)<BR>\n" );
document.write( "(y-16)(y+4) = 0<BR>\n" );
document.write( "y =16 or y =-4\r<BR>\n" );
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document.write( "R^2\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje<BR>\n" );
document.write( "Seminole Community College<BR>\n" );
document.write( "Altamonte Springs Campus </SPAN>\n" );
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