document.write( "Question 211372: Could someone please tell me if I did this right.\r
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document.write( "Evaluate the logarithmic equation for three values of x that are greater than 1, three values between 0 and 1, x to =0.
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document.write( "y=log3.5^x\r
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document.write( "x=2 so y=0.55
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document.write( "x=3 so y=0.88
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document.write( "x=4 so y=1.11
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document.write( "x=0.2 so y= - 1.28
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document.write( "x=0.5 so y= - 0.55
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document.write( "x=0.7 so y= - 0.28
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document.write( "x=1 so y=0 \n" );
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Algebra.Com's Answer #159738 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! y=log(3.5^x) \n" ); document.write( ". \n" ); document.write( "x=4,,,,,3.5^4=150,,,,,,log 150 = 2.176 \n" ); document.write( "x=3,,,,,3.5^3=42.9,,,,,log 42.9 =1.632 \n" ); document.write( "x=2,,,,,3.5^2=12.25,,,,log12.25 = 1.088 \n" ); document.write( "x=1,,,,,3.5^1 = 3.5,,,,log 3.5 = .544 \n" ); document.write( "x=.7,,,,3.5^.7=2.40,,,,log 2.40 = .3808 \n" ); document.write( "x=.5,,,,3.5^.5=1.87,,,,log 1.87=.2720 \n" ); document.write( "x=.2,,,,3.5^.2=1.28,,,,log 1.28 = .1088 \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |