document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211365>Question 211365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 82 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159727 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  x=1st integer,  x+2 =  2nd  integer,  and  x+4 = 3rd integer<BR>\n" );
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document.write( "1(x) +2(x+2) +3(x+4) = 82<BR>\n" );
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document.write( "x+2x+4+3x+12 =82<BR>\n" );
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document.write( "6x + 16 =82<BR>\n" );
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document.write( "6x=66<BR>\n" );
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document.write( "x=11<BR>\n" );
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document.write( "Integers  are 11,13,15,<BR>\n" );
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document.write( "check,,11 +2*13 +3*15 = 82,,,,,ok<BR>\n" );
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