document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211364>Question 211364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> train a and b are travelling in the same direction on parallel tracks. train a is travelling at 60 mph and train b at 70 mph. train a passes a station at 7:25 pm. If train b passes the same station at 7:55 pm at what time will train b catch up with train a\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159722 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> train a and b are travelling in the same direction on parallel tracks. train a is travelling at 60 mph and train b at 70 mph. train a passes a station at 7:25 pm. If train b passes the same station at 7:55 pm at what time will train b catch up with train a\"<BR>\n" );
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document.write( "In the 1/2 hour before train B passes the station, train A goes 30 miles (60 mph for 1/2 hour).<BR>\n" );
document.write( "Train B is gaining on Train A at 10 mph (70 - 60).  To gain the 30 miles at 10 mph will take 3 hours (30/10).<BR>\n" );
document.write( "755 + 3 = 10:55 PM<BR>\n" );
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