document.write( "Question 211346This question is from textbook
\n" ); document.write( ": 2/3+3y=5y-2/15 \n" ); document.write( "
Algebra.Com's Answer #159714 by checkley77(12844)\"\" \"About 
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2/3+3y=5y-2/15
\n" ); document.write( "3y-5y=-2/15-2/3
\n" ); document.write( "-2y=(-2-2*5)/15
\n" ); document.write( "-2y=(-2-10)/15
\n" ); document.write( "-2y=-12/15
\n" ); document.write( "-2y=-4/5
\n" ); document.write( "y=(-4/5)/-2
\n" ); document.write( "y=(-4/5)(1/-2)
\n" ); document.write( "y=4/10
\n" ); document.write( "y=2/5 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "2/3+3(2/5)=5(2/5)-2/15
\n" ); document.write( "2/3+6/5=10/5-2/15
\n" ); document.write( "(2*5+6*3)/15=(10*3-2)/15
\n" ); document.write( "(10+18)/15=(30-2)/15
\n" ); document.write( "28/15=28/15
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