document.write( "Question 211346This question is from textbook
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document.write( ": 2/3+3y=5y-2/15 \n" );
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Algebra.Com's Answer #159714 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2/3+3y=5y-2/15 \n" ); document.write( "3y-5y=-2/15-2/3 \n" ); document.write( "-2y=(-2-2*5)/15 \n" ); document.write( "-2y=(-2-10)/15 \n" ); document.write( "-2y=-12/15 \n" ); document.write( "-2y=-4/5 \n" ); document.write( "y=(-4/5)/-2 \n" ); document.write( "y=(-4/5)(1/-2) \n" ); document.write( "y=4/10 \n" ); document.write( "y=2/5 ans. \n" ); document.write( "Proof: \n" ); document.write( "2/3+3(2/5)=5(2/5)-2/15 \n" ); document.write( "2/3+6/5=10/5-2/15 \n" ); document.write( "(2*5+6*3)/15=(10*3-2)/15 \n" ); document.write( "(10+18)/15=(30-2)/15 \n" ); document.write( "28/15=28/15 \n" ); document.write( " |