document.write( "Question 211262: Find three consecutive integers such that the sum of the first plus one-third of the second plus three-fourths of the third is 31. \n" ); document.write( "
Algebra.Com's Answer #159682 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
Find three consecutive integers such that the sum of the first plus one-third of the second plus three-fourths of the third is 31. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let the 1st number be F
\n" ); document.write( "Then the 2nd and 3rd numbers are (F + 1) and (F + 2), respectively\r
\n" ); document.write( "\n" ); document.write( "Since the sum of the 1st, one-third of the second, and three-fourths of the 3rd is 31,
\n" ); document.write( "then: \"F++%2B++%281%2F3%29%2A%28F+%2B+1%29+%2B++%283%2F4%29%2A%28F+%2B+2%29+=+31\" \r
\n" ); document.write( "\n" ); document.write( "Multiply the equation by the LCD, 12 to get: 12F + 4F + 4 + 9F + 18 = 372
\n" ); document.write( "25F = 350\r
\n" ); document.write( "\n" ); document.write( "F = \"350%2F25\" = 14\r
\n" ); document.write( "\n" ); document.write( "Since F, or the 1st number is 14, the 3 consecutive integers are: \"highlight_green%2814_15_and_16%29\"\r
\n" ); document.write( "\n" ); document.write( "------------------
\n" ); document.write( "Check
\n" ); document.write( "------------------
\n" ); document.write( "The 1st, plus \"1%2F3\" of 15 (the second), plus \"3%2F4\" of 16 (the 3rd number) equals 31, or,\r
\n" ); document.write( "\n" ); document.write( "\"14+%2B+%281%2F3%29%2A15+%2B+%283%2F4%29%2A16+=+31\"\r
\n" ); document.write( "\n" ); document.write( "\"14+%2B+5+%2B+12+=+31\" \r
\n" ); document.write( "\n" ); document.write( "31 = 31 (TRUE)
\n" ); document.write( "
\n" ); document.write( "
\n" );