document.write( "Question 211262: Find three consecutive integers such that the sum of the first plus one-third of the second plus three-fourths of the third is 31. \n" ); document.write( "
Algebra.Com's Answer #159682 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! Find three consecutive integers such that the sum of the first plus one-third of the second plus three-fourths of the third is 31. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the 1st number be F \n" ); document.write( "Then the 2nd and 3rd numbers are (F + 1) and (F + 2), respectively\r \n" ); document.write( "\n" ); document.write( "Since the sum of the 1st, one-third of the second, and three-fourths of the 3rd is 31, \n" ); document.write( "then: \n" ); document.write( "\n" ); document.write( "Multiply the equation by the LCD, 12 to get: 12F + 4F + 4 + 9F + 18 = 372 \n" ); document.write( "25F = 350\r \n" ); document.write( "\n" ); document.write( "F = \n" ); document.write( "\n" ); document.write( "Since F, or the 1st number is 14, the 3 consecutive integers are: \n" ); document.write( "\n" ); document.write( "------------------ \n" ); document.write( "Check \n" ); document.write( "------------------ \n" ); document.write( "The 1st, plus \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "31 = 31 (TRUE) \n" ); document.write( " \n" ); document.write( " |