document.write( "Question 211145: you have 55 coins totaling $10.00. There are more nickels than pennies, more dimes than nickels and more quarters than dimes. How many of each coin do you have? \n" ); document.write( "
Algebra.Com's Answer #159659 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
you have 55 coins totaling $10.00.
\n" ); document.write( "There are more nickels than pennies, more dimes than nickels and more quarters than dimes.
\n" ); document.write( "How many of each coin do you have?
\n" ); document.write( ":
\n" ); document.write( "p + n + d + q = 55
\n" ); document.write( ":
\n" ); document.write( "A lot of unknown here, have to make some assumptions,
\n" ); document.write( " has to be a lot of quarters; assume there are 35 quarters
\n" ); document.write( "then
\n" ); document.write( "p + n + d = 55 - 35
\n" ); document.write( "p + n + d = 20
\n" ); document.write( "and
\n" ); document.write( ".01p + .05n + .10d = 10 - 8.75
\n" ); document.write( ".01p + .05n + .10d = 1.25
\n" ); document.write( "Multiply by 100
\n" ); document.write( "p + 5n + 10d = 125
\n" ); document.write( ":
\n" ); document.write( "subtract the 1st equation from the above equation:
\n" ); document.write( "p + 5n + 10d = 125
\n" ); document.write( "p + n + d = 20
\n" ); document.write( "------------------------- subtraction eliminates p
\n" ); document.write( "0p + 4n + 9d = 105
\n" ); document.write( ":
\n" ); document.write( "4n = 105 - 9d
\n" ); document.write( "n = \"%28105+-+9d%29%2F4\"
\n" ); document.write( "Try values for d which give an positive integer value for n that is less than d (only have one)
\n" ); document.write( ":
\n" ); document.write( "d = 9 then n = 6
\n" ); document.write( "find p
\n" ); document.write( "p = 20 - 9 - 6
\n" ); document.write( "p = 5
\n" ); document.write( ":
\n" ); document.write( "so we have 5 pennies, 6 nickels, 9 dimes and 35 quarters (55 coins)
\n" ); document.write( ":
\n" ); document.write( "Check the value:
\n" ); document.write( ".01(5) + .05(6) + .10(9) + .25(35) = 10.00
\n" ); document.write( ".05 + .30 + .90 + 8.75 = 10\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );