document.write( "Question 211300: logx (1/8) = -3
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Algebra.Com's Answer #159650 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Remember that if \"log%28b%2C%28x%29%29=y\", then \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "In this case, since \"log%28x%2C%281%2F8%29%29=-3\", this means that \"x%5E%28-3%29=1%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E%28-3%29=1%2F8\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28x%5E3%29=1%2F8\" Rewrite \"x%5E%28-3%29\" as \"1%2F%28x%5E3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2A8=1%2Ax%5E3\" Cross multiply\r
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\n" ); document.write( "\n" ); document.write( "\"8=x%5E3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3=8\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=root%283%2C8%29\" Take the cube root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Take the cube root of 8 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=2\"\r
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