document.write( "Question 211163: A hose can fill a swimming pool in 6 hours. Another hose needs 3 more hours to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool. \n" ); document.write( "
Algebra.Com's Answer #159627 by Alan3354(69443)\"\" \"About 
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A hose can fill a swimming pool in 6 hours. Another hose needs 3 more hours to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool.
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\n" ); document.write( "h1 takes 6 hours, so it fills 1/6 pool per hour.
\n" ); document.write( "h2 takes x hours, so it fills 1/x pool per hour.
\n" ); document.write( "Together, they do 1/6 + 1/x per hour.
\n" ); document.write( "1/6 + 1/x = (x+6)/6x per hour (together), so it takes 6x/(x+6) hours.
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\n" ); document.write( "The time the 2nd hose takes, x hours, is 3 hours more than the time together.
\n" ); document.write( "x-3 = 6x/(x+6)
\n" ); document.write( "(x-3)*(x+6) = 6x
\n" ); document.write( "\"x%5E2+%2B+3x+-+18+=+6x\"
\n" ); document.write( "\"x%5E2+-+3x+-+18+=+0\"
\n" ); document.write( "(x-6)*(x+3) = 0
\n" ); document.write( "x = 6 hours (Ignore the -3 hours)
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\n" ); document.write( "Each hose takes 6 hours. Together they take 3 hours, so the time for the 2nd hose is 3 hours more than the 3 hours together.
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