document.write( "Question 29117: hi. i was assigned to show that there are 43411 consequtive composite numbers. ok, i know that i can do 43411! and if i`ll divide the whole thing by,
\n" ); document.write( "say n!+3 I`d be left with the composites. or should i do n! +1 but to start dividing from 43410! instead? thanks.
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Algebra.Com's Answer #15962 by venugopalramana(3286)\"\" \"About 
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\n" ); document.write( "hi. i was assigned to show that there are 43411 consequtive composite numbers. ok, i know that i can do 43411!
\n" ); document.write( "NO YOU NEED TO TAKE (43411+1)!=43412! AND THEN THE 43411 CONSECUTIVE NUMBERS ARE
\n" ); document.write( "43412!+2,43412!+3,43412!+4,43412!+5,43412!+6,43412!+7,43412!+8,43412!+9........
\n" ); document.write( ".......43412!+43409,43412!+43410,43412!+43411,43412!+43412.\r
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\n" ); document.write( "\n" ); document.write( "and if i`ll divide the whole thing by,
\n" ); document.write( "NO... NO DIVISION NEEDED ..JUST LIST THE NUMBERS AS GIVEN ABOVE.
\n" ); document.write( "say n!+3
\n" ); document.write( "NO... NO DIVISION NEEDED ..JUST LIST THE NUMBERS AS GIVEN ABOVE
\n" ); document.write( "I`d be left with the composites. or should i do n! +1 but to start dividing
\n" ); document.write( "NO... NO DIVISION NEEDED ..JUST LIST THE NUMBERS AS GIVEN ABOVE
\n" ); document.write( " from 43410! instead?
\n" ); document.write( " NO... NO DIVISION NEEDED ..JUST LIST THE NUMBERS AS GIVEN ABOVE
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