document.write( "Question 210963: Solve the linear system: 2x + 7y = 41, 2y = 3x + 1 \n" ); document.write( "

Algebra.Com's Answer #159613 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Solve the linear system: 2x + 7y = 41, 2y = 3x + 1
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\n" ); document.write( "We can rearrange this to use elimination
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\n" ); document.write( "+2x + 7y = 41
\n" ); document.write( "-3x + 2y = 1
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\n" ); document.write( "Multiply 1st equation by 3, multiply the 2nd equation by 2
\n" ); document.write( "+6x + 21y = 123
\n" ); document.write( "-6x + 4y = 2
\n" ); document.write( "---------------addition eliminates x, find y
\n" ); document.write( "0 + 25y = 125
\n" ); document.write( "y = $\"125%2F25\"$
\n" ); document.write( "y = 5
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\n" ); document.write( "Find x using the 1st original equation
\n" ); document.write( "2x + 7(5) = 41,
\n" ); document.write( "2x + 35 = 41
\n" ); document.write( "2x = 41 - 35
\n" ); document.write( "x = $\"6%2F2\"$
\n" ); document.write( "x = 3
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\n" ); document.write( "Check solution in 2nd original equation:
\n" ); document.write( "2(5) = 3(3) + 1 \n" ); document.write( "

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