document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211184>Question 211184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Aris is three years older than Rosie. In seven years, Aries will be twice as old as Rosie was five years ago. How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159604 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = Aris' age now and R = Rosie's age now.<BR>\n" );
document.write( "1) A = R+3 \"Aris is three years older than Rosie.\"<BR>\n" );
document.write( "2) A+7 = 2(R-5) \"In seven years, Aris will be twice as old as Rosie was five years ago.\"<BR>\n" );
document.write( "Substitute A = R+3 into equation 2) and solve for R.<BR>\n" );
document.write( "(R+3)+7 = 2(R-5) Simplify.<BR>\n" );
document.write( "R+10 = 2R-10 Subtract R from both sides.<BR>\n" );
document.write( "10 = R-10 Add 10 to both sides.<BR>\n" );
document.write( "20 = R<BR>\n" );
document.write( "Rosie is 20 years old.<BR>\n" );
document.write( "A = R+3<BR>\n" );
document.write( "A = 23<BR>\n" );
document.write( "Aris is 23 years old. </SPAN>\n" );
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