document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211183>Question 211183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Not sure if this question belong here but it has to do with percentage change.<BR>\n" );
document.write( "The question is-<BR>\n" );
document.write( "the power of an electric circuit is given by P=I^2 R whre I= current and R= resistance\r<BR>\n" );
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document.write( "Find the % change in Power if the current is halved and resistance decreases by 25%.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159582 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = I^2R<BR>\n" );
document.write( "(I/2)^2*(0.75R) = (I^2/4)*0.75R<BR>\n" );
document.write( "= 0.1875(I^2R)<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "The change is a reduction of 13/16 from the original.<BR>\n" );
document.write( "13/16 = 0.8125 = 81.25%<BR>\n" );
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document.write( "Another approach:<BR>\n" );
document.write( "V = IR (volts = I*R)<BR>\n" );
document.write( "P = VI (watts = volts * amps)<BR>\n" );
document.write( "V = IR --> (0.5I)*(0.75R)<BR>\n" );
document.write( "V --> 0.375IR<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "P = 0.375IR*0.5I --> 0.1875I^2R<BR>\n" );
document.write( " </SPAN>\n" );
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