document.write( "Question 211220: You drive 1500 miles to California. On the way home, you averaged 10 miles per hour less, and the drive took you 5 extra hours. What was your average speed on the way to California? \n" ); document.write( "
Algebra.Com's Answer #159581 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "T=1500/R
\n" ); document.write( "1500=(R-10)(T+5)
\n" ); document.write( "1500=(R-10)(1500/R+5)
\n" ); document.write( "1500=1500-15000/R+5R-50
\n" ); document.write( "0=-15000/R+5R-50
\n" ); document.write( "(-15000+5R*R)/R=50
\n" ); document.write( "-15000+5R^2=50R
\n" ); document.write( "-15000+5R^2-50R=0
\n" ); document.write( "5R^2-50R-15000=0
\n" ); document.write( "5(R^2-10R-3000)=0
\n" ); document.write( "5(R-60)(R+50)=0
\n" ); document.write( "R-60=0
\n" ); document.write( "R=60 MPH. FOR THE TRIP TO CALIFORNIA.
\n" ); document.write( "1500/60=25 HOURS FOR THE TRIP TO CALIFORNIA.
\n" ); document.write( "1500=(60-10)(25+5)
\n" ); document.write( "1500=50*30
\n" ); document.write( "1500=1500
\n" ); document.write( "
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