document.write( "Question 211220: You drive 1500 miles to California. On the way home, you averaged 10 miles per hour less, and the drive took you 5 extra hours. What was your average speed on the way to California? \n" ); document.write( "
Algebra.Com's Answer #159581 by checkley77(12844) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "T=1500/R \n" ); document.write( "1500=(R-10)(T+5) \n" ); document.write( "1500=(R-10)(1500/R+5) \n" ); document.write( "1500=1500-15000/R+5R-50 \n" ); document.write( "0=-15000/R+5R-50 \n" ); document.write( "(-15000+5R*R)/R=50 \n" ); document.write( "-15000+5R^2=50R \n" ); document.write( "-15000+5R^2-50R=0 \n" ); document.write( "5R^2-50R-15000=0 \n" ); document.write( "5(R^2-10R-3000)=0 \n" ); document.write( "5(R-60)(R+50)=0 \n" ); document.write( "R-60=0 \n" ); document.write( "R=60 MPH. FOR THE TRIP TO CALIFORNIA. \n" ); document.write( "1500/60=25 HOURS FOR THE TRIP TO CALIFORNIA. \n" ); document.write( "1500=(60-10)(25+5) \n" ); document.write( "1500=50*30 \n" ); document.write( "1500=1500 \n" ); document.write( " |