document.write( "Question 211150: The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 33 cm^2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #159572 by edjones(8007) You can put this solution on YOUR website! L=w+1 \n" ); document.write( "wL=A \n" ); document.write( "w(w+1)=33 \n" ); document.write( "w^2+w-33=0 \n" ); document.write( "w=5.266... Quadratic formula \n" ); document.write( "L=6.266... \n" ); document.write( ". \n" ); document.write( "a^2+b^2=c^2 \n" ); document.write( "(5.266)^2+(6.266)^2=67 \n" ); document.write( "sqrt(67)cm is the length of the diagonal. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( ". \n" ); document.write( "
|