document.write( "Question 211150: The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 33 cm^2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #159572 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
L=w+1
\n" ); document.write( "wL=A
\n" ); document.write( "w(w+1)=33
\n" ); document.write( "w^2+w-33=0
\n" ); document.write( "w=5.266... Quadratic formula
\n" ); document.write( "L=6.266...
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\n" ); document.write( "a^2+b^2=c^2
\n" ); document.write( "(5.266)^2+(6.266)^2=67
\n" ); document.write( "sqrt(67)cm is the length of the diagonal.
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\n" ); document.write( "Ed
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B-33+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-33=133\".
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\n" ); document.write( " Discriminant d=133 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+133+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+133+%29%29%2F2%5C1+=+5.2662812973354\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+133+%29%29%2F2%5C1+=+-6.2662812973354\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B1x%2B-33\" can be factored:
\n" ); document.write( " \"1x%5E2%2B1x%2B-33+=+1%28x-5.2662812973354%29%2A%28x--6.2662812973354%29\"
\n" ); document.write( " Again, the answer is: 5.2662812973354, -6.2662812973354.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-33+%29\"
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