document.write( "Question 211170: Ths is a summer math problem I was assigned to complete. A punter can kick a football with an initial velocity of 48 feet per second. How many seconds will it take for the ball to return to the ground?(Hint: Use the formula h=vt-16t2*)I was unsure whether or not this formula was correct for some reason I thought the formula was h=v-16t2*. I still need help wth completing the problem though. Thank you in adance the sooner this is answered the better.\r
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Algebra.Com's Answer #159535 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"h=vt-16t%5E2\" Start with the given formula\r
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\n" ); document.write( "\n" ); document.write( "\"h=48t-16t%5E2\" Plug in the given velocity of \"v=48\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=48t-16t%5E2\" Plug in the height of 0 \"h=0\" (since the height is zero at the ground)\r
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\n" ); document.write( "\n" ); document.write( "\"0=-16t%5E2%2B48t\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"-16t%5E2%2B48t\" is in the form of \"At%5E2%2BBt%2BC\" where \"A=-16\", \"B=48\", and \"C=0\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"t\":\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%2848%29+%2B-+sqrt%28+%2848%29%5E2-4%28-16%29%280%29+%29%29%2F%282%28-16%29%29\" Plug in \"A=-16\", \"B=48\", and \"C=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48+%2B-+sqrt%28+2304-4%28-16%29%280%29+%29%29%2F%282%28-16%29%29\" Square \"48\" to get \"2304\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48+%2B-+sqrt%28+2304-0+%29%29%2F%282%28-16%29%29\" Multiply \"4%28-16%29%280%29\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48+%2B-+sqrt%28+2304+%29%29%2F%282%28-16%29%29\" Subtract \"0\" from \"2304\" to get \"2304\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48+%2B-+sqrt%28+2304+%29%29%2F%28-32%29\" Multiply \"2\" and \"-16\" to get \"-32\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48+%2B-+48%29%2F%28-32%29\" Take the square root of \"2304\" to get \"48\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-48+%2B+48%29%2F%28-32%29\" or \"t+=+%28-48+-+48%29%2F%28-32%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%280%29%2F%28-32%29\" or \"t+=++%28-96%29%2F%28-32%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+0\" or \"t+=+3\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"t+=+0\" or \"t+=+3\" \r
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\n" ); document.write( "\n" ); document.write( "This means that at times of 0 and 3 seconds, the ball will be at the ground. \r
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\n" ); document.write( "\n" ); document.write( "Since we already know that the ball is at the ground at 0 seconds, the other solution \"t=3\" is more interesting. So we're going to ignore \"t=0\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So it will take 3 seconds for the ball to return to the ground.
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