document.write( "Question 211087: This problem in extra work but i am confused. If anyone can help thanks.
\n" ); document.write( "Solve algebraically, using the five step method. Show all steps.\r
\n" ); document.write( "\n" ); document.write( "The area of a rectangle in 525cm^2 Find the dimensions of a rectangle if the ratio of the length to the width is 7:3 \n" ); document.write( "

Algebra.Com's Answer #159501 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The area of a rectangle in 525cm^2
\n" ); document.write( "Find the dimensions of a rectangle if the ratio of the length to the width is 7:3
\n" ); document.write( ":
\n" ); document.write( "let x = the multiplier
\n" ); document.write( "then
\n" ); document.write( "7x = the length
\n" ); document.write( "and
\n" ); document.write( "3x = the width
\n" ); document.write( ":
\n" ); document.write( "Area equation (L*W)
\n" ); document.write( "7x * 3x = 525
\n" ); document.write( "21x^2 = 525
\n" ); document.write( "Divide both sides by 21, results
\n" ); document.write( "x^2 = 25
\n" ); document.write( "x = 5 is the multiplier
\n" ); document.write( "then
\n" ); document.write( "5*7 = 35 is the length
\n" ); document.write( "and
\n" ); document.write( "5*3 = 15 is the width
\n" ); document.write( ";
\n" ); document.write( "Check; 35 * 15 = 525 \n" ); document.write( "

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