document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211099>Question 211099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 2 numbers is 25. 12 less than 4 times one of the numbers is 16 more than twice the other number. Find both numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159494 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two numbers be a and b.<BR>\n" );
document.write( "a+b = 25 \"The sum of two numbers is 25.\"<BR>\n" );
document.write( "4a-12 = 2b+16 \"12 less than 4 times one of the numbers (4a-12) is 16 more than twice the other number(2b+16).\"<BR>\n" );
document.write( "Rewrite the first equation as: a = 25-b and substitute into the second equation.<BR>\n" );
document.write( "4(25-b)-12 = 2b+16 Simplify and solve for b.<BR>\n" );
document.write( "100-4b-12 = 2b+16 Add 4b to both sides.<BR>\n" );
document.write( "88 = 6b+16 Subtract 16 from both sides.<BR>\n" );
document.write( "72 = 6b Divide both sides by 6.<BR>\n" );
document.write( "12 = b and...<BR>\n" );
document.write( "a = 25-b<BR>\n" );
document.write( "a = 25-12<BR>\n" );
document.write( "a = 13<BR>\n" );
document.write( "The two numbers are 12 and 13.\r<BR>\n" );
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