document.write( "Question 211047: A sum of $2100 is invested in two accounts, one earning 7% simple annual interest and one earning 4%. If the total interest earned for the year is $120, how much money is in each account? \n" ); document.write( "
Algebra.Com's Answer #159473 by math problem solving(30)\"\" \"About 
You can put this solution on YOUR website!
Let x be the amount of money invested at 7%.
\n" ); document.write( "Then the amount invested at 4% is 2100 - x.\r
\n" ); document.write( "\n" ); document.write( "The interest earned from the money invested at 7% is x*7%
\n" ); document.write( "The interest earned from the money invested at 4% is (2100 - x)*4%\r
\n" ); document.write( "\n" ); document.write( "As the total interest earned from the two investments is given as $120, we have:
\n" ); document.write( "x*7% + (2100 - x)*4% = 120\r
\n" ); document.write( "\n" ); document.write( "Solving for x, we get
\n" ); document.write( "7x + 4(2100 - x) = 12000 (multiply both sides by 100)
\n" ); document.write( "7x + 8400 - 4x = 12000
\n" ); document.write( "3x + 8400 = 12000
\n" ); document.write( "3x = 3600
\n" ); document.write( "x = 1200\r
\n" ); document.write( "\n" ); document.write( "So $1200 is invested at 7%, and $2100 - $1200 = $900 is invested at 4%.
\n" ); document.write( "
\n" ); document.write( "
\n" );