document.write( "Question 211047: A sum of $2100 is invested in two accounts, one earning 7% simple annual interest and one earning 4%. If the total interest earned for the year is $120, how much money is in each account? \n" ); document.write( "
Algebra.Com's Answer #159473 by math problem solving(30)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the amount of money invested at 7%. \n" ); document.write( "Then the amount invested at 4% is 2100 - x.\r \n" ); document.write( "\n" ); document.write( "The interest earned from the money invested at 7% is x*7% \n" ); document.write( "The interest earned from the money invested at 4% is (2100 - x)*4%\r \n" ); document.write( "\n" ); document.write( "As the total interest earned from the two investments is given as $120, we have: \n" ); document.write( "x*7% + (2100 - x)*4% = 120\r \n" ); document.write( "\n" ); document.write( "Solving for x, we get \n" ); document.write( "7x + 4(2100 - x) = 12000 (multiply both sides by 100) \n" ); document.write( "7x + 8400 - 4x = 12000 \n" ); document.write( "3x + 8400 = 12000 \n" ); document.write( "3x = 3600 \n" ); document.write( "x = 1200\r \n" ); document.write( "\n" ); document.write( "So $1200 is invested at 7%, and $2100 - $1200 = $900 is invested at 4%. \n" ); document.write( " \n" ); document.write( " |