document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211043>Question 211043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please explain this to me? I think I understand whats going on but I'm still getting a bit confused. Heres the question:\r<BR>\n" );
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document.write( "The length of a rectange is 3 m more than twice its width, and the area of the rectange is 35 m^2. Findthe dimensions of the rectangle. \r<BR>\n" );
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document.write( "Thank you in advance!\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159431 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 m more than twice its width, and the area of the rectangle is 35 m^2. Findthe dimensions of the rectangle. <BR>\n" );
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document.write( "L = 2W+3<BR>\n" );
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document.write( "Area = W*L<BR>\n" );
document.write( "35 = W(2W+3)<BR>\n" );
document.write( "2W^2 + 3W - 35 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "2W^2 + 10W-7W - 35 = 0<BR>\n" );
document.write( "2W(W+5) -7(W+5) = 0<BR>\n" );
document.write( "(W+5)(2W-7) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "2W-7 = 0<BR>\n" );
document.write( "W = 3.5 meters (width)<BR>\n" );
document.write( "L = 2W+3 = 10 meters (length) <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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