document.write( "Question 211034: a few questions that i need to check my work on\r
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document.write( "The length (L) of a rectangle is 2 feet less than 10 times its width (W). If the perimeter of the rectangle is 62 feet, find the rectangle's dimensions.\r
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document.write( "The perimeter of a rectangle is 78 inches. If the length of the rectangle is seven inches more than three times the width, find the dimensions. \n" );
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Algebra.Com's Answer #159425 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=10W-2 \n" ); document.write( "2L+2W=62 \n" ); document.write( "2(10W-2)+2W=62 \n" ); document.write( "20W-4+2W=62 \n" ); document.write( "22W=62+4 \n" ); document.write( "22W=66 \n" ); document.write( "W=66/22 \n" ); document.write( "W=3 FT. \n" ); document.write( "L=10*3-2 \n" ); document.write( "L=30-2 \n" ); document.write( "L=28 FT. \n" ); document.write( "PROOF: \n" ); document.write( "2*28+2*3=62 \n" ); document.write( "56+6=62 \n" ); document.write( "62=62 \n" ); document.write( "------------------------------------- \n" ); document.write( "2(3W+7)+2W=78 \n" ); document.write( "6W+14+2W=78 \n" ); document.write( "8W=78-14 \n" ); document.write( "8W=64 \n" ); document.write( "W=64/8 \n" ); document.write( "W=8 IN. \n" ); document.write( "L=3*8+7 \n" ); document.write( "L=24+7 \n" ); document.write( "L=31 IN. \n" ); document.write( "PROOF: \n" ); document.write( "2*31+2*8=78 \n" ); document.write( "62+16=78 \n" ); document.write( "78=78 \n" ); document.write( " \n" ); document.write( " |