document.write( "Question 211034: a few questions that i need to check my work on\r
\n" ); document.write( "\n" ); document.write( "The length (L) of a rectangle is 2 feet less than 10 times its width (W). If the perimeter of the rectangle is 62 feet, find the rectangle's dimensions.\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 78 inches. If the length of the rectangle is seven inches more than three times the width, find the dimensions.
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Algebra.Com's Answer #159425 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
L=10W-2
\n" ); document.write( "2L+2W=62
\n" ); document.write( "2(10W-2)+2W=62
\n" ); document.write( "20W-4+2W=62
\n" ); document.write( "22W=62+4
\n" ); document.write( "22W=66
\n" ); document.write( "W=66/22
\n" ); document.write( "W=3 FT.
\n" ); document.write( "L=10*3-2
\n" ); document.write( "L=30-2
\n" ); document.write( "L=28 FT.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*28+2*3=62
\n" ); document.write( "56+6=62
\n" ); document.write( "62=62
\n" ); document.write( "-------------------------------------
\n" ); document.write( "2(3W+7)+2W=78
\n" ); document.write( "6W+14+2W=78
\n" ); document.write( "8W=78-14
\n" ); document.write( "8W=64
\n" ); document.write( "W=64/8
\n" ); document.write( "W=8 IN.
\n" ); document.write( "L=3*8+7
\n" ); document.write( "L=24+7
\n" ); document.write( "L=31 IN.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*31+2*8=78
\n" ); document.write( "62+16=78
\n" ); document.write( "78=78
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