document.write( "Question 211035: Using the Library, web resources, and/or other materials, find a real-life application of a quadratic function. State the application, give the equation of the quadratic function, and state what the x and y in the application represent. Choose at least two values of x to input into your function and find the corresponding y for each. State, in words, what each x and y means in terms of your real-life application. Please see the following example. Do not use any version of this example in your own post. You may use other variables besides x and y, such as t and S depicted in the following example, but you may not use that example. Be sure to reference all sources using APA style.\r
\n" ); document.write( "\n" ); document.write( "Typing hint: To type x-squared, use x^2. Do not use special graphs or symbols because they will not appear when pasted to the Discussion Board.\r
\n" ); document.write( "\n" ); document.write( "When thrown into the air from the top of a 50 ft building, a ball’s height, S, at time t can be found by S(t) = -16t^2 + 32t + 50. When t = 1, s = -16(1)^2 + 32(1) + 50 = 66. This implies that after 1 second, the height of the ball is 66 feet. When t = 2, s = -16(2)^2 + 32(2) + 50 = 50. This implies that after 2 seconds, the height of the ball is 50 feet.\r
\n" ); document.write( "\n" ); document.write( "I used this. I wanted to know if I was correct.\r
\n" ); document.write( "\n" ); document.write( "Real life quadratic function application:\r
\n" ); document.write( "\n" ); document.write( "The formula s=-16t^2+vOt+sO\r
\n" ); document.write( "\n" ); document.write( "sO=initial height
\n" ); document.write( "vO=velocity in feet per second
\n" ); document.write( "t=time\r
\n" ); document.write( "\n" ); document.write( "The initial height of the mountain where you are standing is 300 feet.\r
\n" ); document.write( "\n" ); document.write( "I launch a rock in the air at 52 feet per second.
\n" ); document.write( "I want to find out how high it will be after 3 seconds. \r
\n" ); document.write( "\n" ); document.write( "Now let’s do the formula.
\n" ); document.write( "s=-16t^2+vOt+sO
\n" ); document.write( "=-16(3) ^2+52(3) +300
\n" ); document.write( "=-16(9) +156+300
\n" ); document.write( "=-144+465
\n" ); document.write( "s=312\r
\n" ); document.write( "\n" ); document.write( "So at 3 seconds, it's 312\r
\n" ); document.write( "\n" ); document.write( "This accurately describes the rock's height at any given time from the time of launch to the time.\r
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\n" ); document.write( "

Algebra.Com's Answer #159419 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Good work.
\n" ); document.write( "You will find other examples by using Google to search for quadratic
\n" ); document.write( "applications.
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\n" ); document.write( "Also, the formula does not give the height at \"all times\": only for the
\n" ); document.write( "times the ball is in the air or the instant it reaches the ground.
\n" ); document.write( "After that the answers will be negative and therefore not applicable.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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