document.write( "Question 211001: How much solution of Hydrochloric acid at 11% concentration should be mixed with 8% concentratrion to produce a solution of 800 milliliters at 10%? \n" ); document.write( "

Algebra.Com's Answer #159402 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
How much solution of Hydrochloric acid at 11% concentration should be mixed
\n" ); document.write( " with 8% concentration to produce a solution of 800 milliliters at 10%?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 11% stuff
\n" ); document.write( "Resulting amt is to be 800 ml, therefore
\n" ); document.write( "(800-x) = amt of 8% stuff
\n" ); document.write( ":
\n" ); document.write( ".11x + .08(800-x) = .10(800)
\n" ); document.write( ":
\n" ); document.write( ".11x + 64 - .08x = 80
\n" ); document.write( ":
\n" ); document.write( ".11x - .08x = 80 - 64
\n" ); document.write( ":
\n" ); document.write( ".03x = 16
\n" ); document.write( "x = $\"16%2F.03\"$
\n" ); document.write( "x = 533 $\"1%2F3\"$ ml of 11% stuff
\n" ); document.write( "then
\n" ); document.write( "800 - 533 $\"1%2F3\"$ = 266 $\"2%2F3\"$ of 8% stuff
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using decimals
\n" ); document.write( ".11(533.33) + .08(266.67) = .10(800)
\n" ); document.write( "58.67 + 21.33 = 80 \n" ); document.write( "

\n" );