document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210703>Question 210703</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321296443/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A mixture of nuts contains almonds worth .50 cents a pound, cashews worth $1.00 per pound, and pecans worth .75 cents per pound. If there are three times as many pounds of almonds as cashews in a 100-pound mixture worth .70 cents per pound, how many pounds of each nut does the mixture contain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159383 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  mixture of nuts contains almonds worth .50 cents a pound, cashews worth $1.00<BR>\n" );
document.write( " per pound, and pecans worth .75 cents per pound. <BR>\n" );
document.write( "If there are three times as many pounds of almonds as cashews in a 100-pound<BR>\n" );
document.write( " mixture worth .70 cents per pound, how many pounds of each nut does the mixture contain?<BR>\n" );
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document.write( "Let a = no. of lbs of almonds<BR>\n" );
document.write( "Let c = no. of lbs of cashews<BR>\n" );
document.write( "Let p = no. of lbs of pecans<BR>\n" );
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document.write( ".50a + 1.00c + .75p = .70(100)<BR>\n" );
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document.write( "\"three times as many pounds of almonds as cashews\"<BR>\n" );
document.write( "a = 3c<BR>\n" );
document.write( "then we can say<BR>\n" );
document.write( "p = (100 - a - c)<BR>\n" );
document.write( "Replace a with 3c<BR>\n" );
document.write( "p = (100 - 3c - c)<BR>\n" );
document.write( "p = (100-4c)<BR>\n" );
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document.write( ".5a + 1.00c + .75p = .70(100)<BR>\n" );
document.write( "Replace a and p with the above expressions <BR>\n" );
document.write( ".5(3c) + 1(c) + .75(100-4c) = .70(100)<BR>\n" );
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document.write( "1.5c + c + 75 - 3c = 70<BR>\n" );
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document.write( "1.5c + c - 3c = 70 - 75<BR>\n" );
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document.write( "-.5c = -5<BR>\n" );
document.write( "c = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-5%29%2F%28-.5%29 ALIGN=MIDDLE  ALT=\"%28-5%29%2F%28-.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "c = +10 lb of cashews<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3*10 = 30 lb almonds<BR>\n" );
document.write( "and<BR>\n" );
document.write( "10 - 40 = 60 lb of pecans<BR>\n" );
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document.write( "Check solution in original equation<BR>\n" );
document.write( ".50(30) + 1.00(10) + .75(60) = .70(100)<BR>\n" );
document.write( "15 + 10 + 45 = 70<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );