document.write( "Question 210959: The length of a rectangle is 4 feet longer than its width, and its area is 10 sq. feet. Find the length and the width. \r
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Algebra.Com's Answer #159379 by Earlsdon(6294)\"\" \"About 
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Start with:
\n" ); document.write( "\"A+=+L%2AW\" Substitute A = 10 and L = W+4.
\n" ); document.write( "\"10+=+%28W%2B4%29%2AW\" Simplify.
\n" ); document.write( "\"10+=+W%5E2%2B4W\" Subtract 10 from both sides.
\n" ); document.write( "\"W%5E2%2B4W-10+=+0\" Use the quadratic formula to solve:\"W+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" and a = 1, b= 4, and c = -10.
\n" ); document.write( "\"W+=+%28-4%2B-sqrt%284%5E2-4%281%29%28-10%29%29%29%2F2%281%29\" Evaluate.
\n" ); document.write( "\"W+=+%28-4%2B-sqrt%2816-%28-40%29%29%29%2F2\"
\n" ); document.write( "\"W+=+%28-4%2B-sqrt%2856%29%29%2F2\"
\n" ); document.write( "\"W+=+%28-4%2B-sqrt%284%2A14%29%29%2F2\"
\n" ); document.write( "\"W+=+-2%2Bsqrt%2814%29\" or \"W+=+-2-sqrt%2814%29\"
\n" ); document.write( "\"highlight_green%28W+=+1.74%29\" or \"cross%28W+=+-5.74%29\" Discard the negative solution.
\n" ); document.write( "The width is 1.74 feet and the length is 5.74 feet. (Approximately)
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