document.write( "Question 210948: It usually takes Eva 3 hours longer to do the monthly payroll than it takes Cindy. They start working on it together at 9.00 AM and at 5.00 PM they have 90% of it done. If Eva took s 2 hour lunch break while Cindy had none, then how much longer will it take for them to finish the payroll working together?''. \n" ); document.write( "
Algebra.Com's Answer #159356 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! It usually takes Eva 3 hours longer to do the monthly payroll than it takes Cindy. They start working on it together at 9.00 AM and at 5.00 PM they have 90% of it done. If Eva took s 2 hour lunch break while Cindy had none, then how much longer will it take for them to finish the payroll working together? \n" ); document.write( "-------------------------------------- \n" ); document.write( "Cindy's rate is 1/x job/hr \n" ); document.write( "------------- \n" ); document.write( "Eva's rate is 1/(x+3) job/hr \n" ); document.write( "------------------------------- \n" ); document.write( "From 9am to 5pm they have worked 8 hrs \n" ); document.write( "In that time they have accomplished \n" ); document.write( "8*Cindy's rate + 6*Eva's rate = 90% of the job \n" ); document.write( "8(1/x)+6 = 0.90 job \n" ); document.write( "I get x = 24.7 \n" ); document.write( "------------------------------------- \n" ); document.write( "Solve that for \"x\"; then you will know Cindy \n" ); document.write( "and Eva's rates which are 1/x = 1/24.7 and 1/27.7). \n" ); document.write( "--------------------- \n" ); document.write( "To get the time remaining for them to finish \n" ); document.write( "the job. \n" ); document.write( "k(1/24.7 + 1/27.7) = 0.10 of the job \n" ); document.write( "k(0.0766) = 0.10 \n" ); document.write( "k = 1.306 hrs.\r \n" ); document.write( "\n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |