document.write( "Question 210948: It usually takes Eva 3 hours longer to do the monthly payroll than it takes Cindy. They start working on it together at 9.00 AM and at 5.00 PM they have 90% of it done. If Eva took s 2 hour lunch break while Cindy had none, then how much longer will it take for them to finish the payroll working together?''. \n" ); document.write( "
Algebra.Com's Answer #159356 by stanbon(75887)\"\" \"About 
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It usually takes Eva 3 hours longer to do the monthly payroll than it takes Cindy. They start working on it together at 9.00 AM and at 5.00 PM they have 90% of it done. If Eva took s 2 hour lunch break while Cindy had none, then how much longer will it take for them to finish the payroll working together?
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\n" ); document.write( "Cindy's rate is 1/x job/hr
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\n" ); document.write( "Eva's rate is 1/(x+3) job/hr
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\n" ); document.write( "From 9am to 5pm they have worked 8 hrs
\n" ); document.write( "In that time they have accomplished
\n" ); document.write( "8*Cindy's rate + 6*Eva's rate = 90% of the job
\n" ); document.write( "8(1/x)+6 = 0.90 job
\n" ); document.write( "I get x = 24.7
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\n" ); document.write( "Solve that for \"x\"; then you will know Cindy
\n" ); document.write( "and Eva's rates which are 1/x = 1/24.7 and 1/27.7).
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\n" ); document.write( "To get the time remaining for them to finish
\n" ); document.write( "the job.
\n" ); document.write( "k(1/24.7 + 1/27.7) = 0.10 of the job
\n" ); document.write( "k(0.0766) = 0.10
\n" ); document.write( "k = 1.306 hrs.\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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