document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210892>Question 210892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve log(2x-1)-log(x+6)=log5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159312 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     please help me solve log(2x-1)-log(x+6)=log5<BR>\n" );
document.write( ".<BR>\n" );
document.write( "applying log rules:<BR>\n" );
document.write( "log(2x-1)-log(x+6)=log5<BR>\n" );
document.write( "log[(2x-1)/(x+6)]=log5<BR>\n" );
document.write( "(2x-1)/(x+6) = 5<BR>\n" );
document.write( "(2x-1) = 5(x+6)<BR>\n" );
document.write( "2x-1 = 5x+30<BR>\n" );
document.write( "-1 = 3x+30<BR>\n" );
document.write( "-31 = 3x<BR>\n" );
document.write( "-31/3 = x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Just reviewed the answer -- <BR>\n" );
document.write( "when x = -31/3 <BR>\n" );
document.write( "it will produce a log of a NEGATIVE number -- you cannot take a log of a negative number.<BR>\n" );
document.write( "Either there is no solution or your original problem had a typo -- can you please check? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );