document.write( "Question 210794: how many liters of a 25% acid solution must be added to 20 liters of a 45% acid solution to get a 35% acid solution? \n" ); document.write( "
Algebra.Com's Answer #159277 by checkley77(12844)\"\" \"About 
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.45*20+.25X=.35(20+X)
\n" ); document.write( "9+.25X=7+.35X
\n" ); document.write( ".25X-.35X=7-9
\n" ); document.write( "-.1X=2
\n" ); document.write( "X=2/.1
\n" ); document.write( "X=20 LITERS OF 25% ACID IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".45*20+.25*20=.35(20+20)
\n" ); document.write( "9+5=.35*40
\n" ); document.write( "14=14
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