document.write( "Question 210794: how many liters of a 25% acid solution must be added to 20 liters of a 45% acid solution to get a 35% acid solution? \n" ); document.write( "
Algebra.Com's Answer #159277 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .45*20+.25X=.35(20+X) \n" ); document.write( "9+.25X=7+.35X \n" ); document.write( ".25X-.35X=7-9 \n" ); document.write( "-.1X=2 \n" ); document.write( "X=2/.1 \n" ); document.write( "X=20 LITERS OF 25% ACID IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".45*20+.25*20=.35(20+20) \n" ); document.write( "9+5=.35*40 \n" ); document.write( "14=14 \n" ); document.write( " \n" ); document.write( " |