document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29129>Question 29129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solving by elimination\r<BR>\n" );
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document.write( "8x-3y=16,<BR>\n" );
document.write( "8x+3y=-8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15927 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15927\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> add the 2 equations together. This gives you \r<BR>\n" );
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document.write( "16x = 8<BR>\n" );
document.write( "--> x = 8/16<BR>\n" );
document.write( "--> x = 1/2\r<BR>\n" );
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document.write( "So put this into either equation, to find y\r<BR>\n" );
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document.write( "8x-3y=16<BR>\n" );
document.write( "8(1/2)-3y=16<BR>\n" );
document.write( "4 - 3y = 16<BR>\n" );
document.write( "-3y = 12<BR>\n" );
document.write( "y = 12/-3<BR>\n" );
document.write( "y = -4\r<BR>\n" );
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document.write( "put both answers into the other equation and check that the left hand side gives -8 as the answer. If so, then your answers are correct.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
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