document.write( "Question 210784This question is from textbook Intoductery Algebra
\n" ); document.write( ": Please help me solve:\r
\n" ); document.write( "\n" ); document.write( "\"12%2Fsqrt%285x%2B6%29\"=\"sqrt%282x%2B5%29\"\r
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Algebra.Com's Answer #159245 by nyc_function(2741)\"\" \"About 
You can put this solution on YOUR website!
Why not cross-multiply?\r
\n" ); document.write( "\n" ); document.write( "The sqrt{2x + 5} is really over 1.\r
\n" ); document.write( "\n" ); document.write( "12 * 1 = sqrt{5x + 6} * sqrt{2x + 5}\r
\n" ); document.write( "\n" ); document.write( "12 = sqrt{10x^2 + 37x + 30}\r
\n" ); document.write( "\n" ); document.write( "We now have a radical equation.\r
\n" ); document.write( "\n" ); document.write( "Raise both sides to the second power. By doing this, we remove the square root on the right side.\r
\n" ); document.write( "\n" ); document.write( "(12)^2 = [sqrt{10x^2 + 37x + 30}]^2\r
\n" ); document.write( "\n" ); document.write( "12 = 10x^2 + 37x + 30\r
\n" ); document.write( "\n" ); document.write( "Subtract 12 from both sides to create a quadratic equation.\r
\n" ); document.write( "\n" ); document.write( "0 = 10x^2 + 37x + 18\r
\n" ); document.write( "\n" ); document.write( "Can you solve for now x?\r
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