document.write( "Question 3566: How do i determine the equation of this line: parallel to the line -2x+3, containing the point(-2,1)? \n" ); document.write( "
Algebra.Com's Answer #1592 by Pieter(35)\"\" \"About 
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if you know that the general equation for a circle with midpoint M(a,b) is
\n" ); document.write( "(x-a)²+(y-b)²= r², you can work this equation out:
\n" ); document.write( "x² - 2ax + a² + y² - 2by + b² - r² = 0
\n" ); document.write( "if you compare this with x² + 4x + y² - 5 = 0,
\n" ); document.write( "you can conclude that b = 0 (the y coordinate from the midpoint),
\n" ); document.write( "and - 2a = 4 or a = -2
\n" ); document.write( "then we still have a² - r² = -5
\n" ); document.write( "-r² = -5 - 4 = -9 or r² = 9 so r = 3\r
\n" ); document.write( "\n" ); document.write( "So your circle has midpoint M(-2,0) and radius r=3\r
\n" ); document.write( "\n" ); document.write( "i hope you understand the reasoning,
\n" ); document.write( "otherwise contact me\r
\n" ); document.write( "\n" ); document.write( "Greets \n" ); document.write( "
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