document.write( "Question 29114: 4x^3y-20x^y+16xy \n" ); document.write( "
Algebra.Com's Answer #15917 by sdmmadam@yahoo.com(530)\"\" \"About 
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The problem should have been 4x^3y-20x^2y+16xy \r
\n" ); document.write( "\n" ); document.write( "4x^3y-20x^2y+16xy
\n" ); document.write( "=4xy(x^2-5x+4)
\n" ); document.write( "=4xy(x-4)(x-1)
\n" ); document.write( "Answer: 4xy(x-4)(x-1)\r
\n" ); document.write( "\n" ); document.write( "Explanation: Take out 4xy common
\n" ); document.write( "What is inside the bracket is a quadratic expression in x
\n" ); document.write( "And (x^2-5x+4)= x^2-4x-x+4 (splitting the term in x into two parts whose sum is the middle term and whose product if the product of the square term andthe constant term.
\n" ); document.write( "Product of the square term and the constant term
\n" ); document.write( "=(x^2)(4) = (1X2X2)x^2= (-4x)X(-x)
\n" ); document.write( "and (-4x) +(-x) = -5x
\n" ); document.write( "(x^2-5x+4)
\n" ); document.write( "=x^2-4x-x+4
\n" ); document.write( "=(x^2-4x)-x+4
\n" ); document.write( "=x(x-4)-1(x-4)
\n" ); document.write( "=xp-p where p = (x-4)
\n" ); document.write( "=p(x-1)
\n" ); document.write( "=(x-4)(x-1)
\n" ); document.write( " \n" ); document.write( "
\n" );