document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209995>Question 209995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the Perimeter of a rectangle is 40 and the diagonal is 12 find the area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159160 by </B><A HREF=/tutors/aboutme.mpl?userid=Tanzem><B>Tanzem(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Tanzem><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(l+b)=40<BR>\n" );
document.write( "l+b=20 (squaring both the sides)<BR>\n" );
document.write( "l2+b2+lb=400....1\r<BR>\n" );
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document.write( "Now diagonal= 12<BR>\n" );
document.write( "its right angle triangle.<BR>\n" );
document.write( "l2+b2= 144......2\r<BR>\n" );
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document.write( "substituting 2 in 1 we get\r<BR>\n" );
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document.write( "144+lb=400<BR>\n" );
document.write( "lb=256 that is area </SPAN>\n" );
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