document.write( "Question 29115: square root 2x-5 = 1+ square root x-3
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document.write( "I understand I have to square both sides. Where I lose it is here:
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document.write( "squaring 1 + square root x-3. My textbook has: 2times square root x-3 (end square root) + (x-3)
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document.write( "Thanks \n" );
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Algebra.Com's Answer #15915 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OK, to remove at least some of the square roots here, you could square both sides, as: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is just like \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Again, square both sides: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(x-7)(x-3) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so x-7=0 OR x-3=0 \n" ); document.write( "so x=7 or x=3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This looks rather long, but i have written out every step on a different line so you can see everything.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |