document.write( "Question 210648This question is from textbook blitzer
\n" ); document.write( ": Hello, I need to solve \"x%5E2+-+6x+%2B+13\" using the quadratic formula.
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Algebra.Com's Answer #159148 by Earlsdon(6294)\"\" \"About 
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Solve:
\n" ); document.write( "\"x%5E2-6x%2B13+=+0\"?
\n" ); document.write( "Using the quadratic formula: \"x+=+%28-b%2B-sqrt%28b%5E-4ac%29%29%2F2a\" and, in this problem: a = 1, b = -6, and c = 13.
\n" ); document.write( "\"x+=+%28-%28-6%29%2B-sqrt%28%28-6%29%5E2-4%281%29%2813%29%29%29%2F2%281%29\" Evaluate:
\n" ); document.write( "\"x+=+%286%2B-sqrt%2836-52%29%29%2F2\"
\n" ); document.write( "\"x+=+%286%2B-sqrt%28-16%29%29%2F2\"
\n" ); document.write( "\"x+=+6%2F2%2Bsqrt%28-16%29%2F2\" or \"x+=+6%2F2-sqrt%28-16%29%2F2\" and these can be simplified to:
\n" ); document.write( "\"x+=+3%2B%284%2F2%29sqrt%28-1%29\" or \"x+=+3-%284%2F2%29sqrt%28-1%29\"
\n" ); document.write( "\"highlight%28x+=+3%2B2i%29\" or \"highlight%28x+=+3-2i%29\"
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