document.write( "Question 210635: Please show me how to work these problems: Solve for x.\r
\n" ); document.write( "\n" ); document.write( " 1. a(3tx-2b) = c(dx-2)\r
\n" ); document.write( "\n" ); document.write( " and\r
\n" ); document.write( "\n" ); document.write( " 2. a-c/x-a = m
\n" ); document.write( "

Algebra.Com's Answer #159144 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "# 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a%283tx-2b%29+=+c%28dx-2%29+\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3atx-2ab=cdx-2c+\" Distribute\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3atx=cdx-2c%2B2ab+\" Add 2ab to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3atx-cdx=-2c%2B2ab+\" Subtract cdx from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%283at-cd%29=-2c%2B2ab+\" Factor out the GCF 'x'\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%28-2c%2B2ab%29%2F%283at-cd%29+\" Divide both sides by \"3at-cd\".
\n" ); document.write( "
\n" );