document.write( "Question 210604: I need help with these two, they're not in the textbook (GEOMETRY) they're on a review sheet I have to do to prepare for our test tomorrow.\r
\n" ); document.write( "\n" ); document.write( "#1) The measure of the supplement of an angle is 32 less than the measure of the angle. Find the measures of the angles.\r
\n" ); document.write( "\n" ); document.write( "#2)The measure of one angle is 12 degrees greater than the measure of its complement. What are the measures of the angles?\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP! Thanks!\r
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Algebra.Com's Answer #159134 by Earlsdon(6294)\"\" \"About 
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#1) Let the angle be A, then:
\n" ); document.write( "180-A = A-32 \"...the supplement of an angle (180-A) is 32 degrees less than the measure of the angle.\"
\n" ); document.write( "180 = 2A-32
\n" ); document.write( "212 = 2A
\n" ); document.write( "A = 106 degrees and its supplement, 180-A = 74 degrees.
\n" ); document.write( "#2) Let the angle be B, then:
\n" ); document.write( "B = (90-B)+12 \"The measure of one angle (B) is 12 degrees greater than the measure of its complement (90-B).\"
\n" ); document.write( "B = 78-B Add B to both sides.
\n" ); document.write( "2B = 78 Divide both sides by 2.
\n" ); document.write( "B = 39 and its complement, 90-B = 51 degrees.
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