document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210587>Question 210587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use dimensional analysis and the given densities to make the following conversations.<BR>\n" );
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document.write( "A. 14.8 g of boron to cm^3 of boron. The density of boron is 2.34g/cm^3<BR>\n" );
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document.write( "B. 4.62g of mercury to cm^3 of mercury. The density of mercury is 13.5 g/cm^3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159123 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use dimensional analysis and the given densities to make the following conversations.\r<BR>\n" );
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document.write( "A. 14.8 g of boron to cm^3 of boron. The density of boron is 2.34g/cm^3<BR>\n" );
document.write( "14.8 gm/2.34 gm/cc = 6.3248 cc of B<BR>\n" );
document.write( "Notice how the units are correct if you get it correct.  If you multiply it, the units would be gm*(gm/cc).  Use the units to make sure you have the correct operation.  cc = cubic centimeter, or cm^3, same as ml = millileter<BR>\n" );
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document.write( "B. 4.62g of mercury to cm^3 of mercury. The density of mercury is 13.5 g/cm^3<BR>\n" );
document.write( "4.62 gm/13.5 gm/cc = 0.34222... cc of Hg<BR>\n" );
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