document.write( "Question 210514: The area of a rectangle is 120 sq. ft. the length is one less than the width. What is the width of the rectangle.
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Algebra.Com's Answer #159058 by checkley77(12844)\"\" \"About 
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L=W-1
\n" ); document.write( "AREA=LW
\n" ); document.write( "120=(W-1)W
\n" ); document.write( "120=W^2-W
\n" ); document.write( "W^2-W-120=0
\n" ); document.write( "\"W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "W=(1+-SQRT[-1^2-4*1*-120])/2*1
\n" ); document.write( "W=(1+-SQRT[1+480])/2
\n" ); document.write( "W=(1+-SQRT481)/2
\n" ); document.write( "W=(1+-21.93)/2
\n" ); document.write( "W=(1+21.93)/2
\n" ); document.write( "W=22.93/2
\n" ); document.write( "W=11.465 ANS.
\n" ); document.write( "L=11.465-1=10.465 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "11.465*10.465=120
\n" ); document.write( "120~120
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