document.write( "Question 210514: The area of a rectangle is 120 sq. ft. the length is one less than the width. What is the width of the rectangle.
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Algebra.Com's Answer #159058 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W-1 \n" ); document.write( "AREA=LW \n" ); document.write( "120=(W-1)W \n" ); document.write( "120=W^2-W \n" ); document.write( "W^2-W-120=0 \n" ); document.write( " \n" ); document.write( "W=(1+-SQRT[-1^2-4*1*-120])/2*1 \n" ); document.write( "W=(1+-SQRT[1+480])/2 \n" ); document.write( "W=(1+-SQRT481)/2 \n" ); document.write( "W=(1+-21.93)/2 \n" ); document.write( "W=(1+21.93)/2 \n" ); document.write( "W=22.93/2 \n" ); document.write( "W=11.465 ANS. \n" ); document.write( "L=11.465-1=10.465 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "11.465*10.465=120 \n" ); document.write( "120~120 \n" ); document.write( " \n" ); document.write( " |