document.write( "Question 210426: Sam is 10 years older than Jack. Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age. Find Jack and Sam's age. \n" ); document.write( "
Algebra.Com's Answer #159026 by ankor@dixie-net.com(22740)\"\" \"About 
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Sam is 10 years older than Jack.
\n" ); document.write( "Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age.
\n" ); document.write( " Find Jack and Sam's age.
\n" ); document.write( ":
\n" ); document.write( "Let j = Jack's age
\n" ); document.write( "Let s = Sam's age
\n" ); document.write( ":
\n" ); document.write( "\"Sam is 10 years older than Jack.\"
\n" ); document.write( "s = j + 10
\n" ); document.write( ":
\n" ); document.write( "\"Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age.\"
\n" ); document.write( "6j - 2s = j + 7
\n" ); document.write( "6j - j = 2s + 7
\n" ); document.write( "5j = 2s + 7
\n" ); document.write( ":
\n" ); document.write( " Find Jack and Sam's age.
\n" ); document.write( ":
\n" ); document.write( "Substitute (j+10) for s in the above equation
\n" ); document.write( "5j = 2(j+10) + 7
\n" ); document.write( "5j = 2j + 20 + 7
\n" ); document.write( "5j - 2j = 27
\n" ); document.write( "3j = 27
\n" ); document.write( "j = \"27%2F3\"
\n" ); document.write( "j = 9 yrs is Jack's age
\n" ); document.write( ":
\n" ); document.write( "s = j + 10
\n" ); document.write( "s = 9 + 10
\n" ); document.write( "s = 19 yrs is Sam's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age.\"
\n" ); document.write( "-2(19) + 6(9) = 9 + 7
\n" ); document.write( "-38 + 54 = 16 \n" ); document.write( "
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