document.write( "Question 210452: Good afteroon. I have a question regarding completing the square. Here is the equation: \"9x%5E2-18x=-3\"\r
\n" ); document.write( "\n" ); document.write( "I keep coming up with x= 1 plus minus .816 but in class the answer was x=3+square root 6 over 3 and x=3-square root 6 over 3. Does that seem correct? If so I just don't know how it got that way? Any help would be appreciated. :)
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Algebra.Com's Answer #159023 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
I am not sure what they are doing in class, but you got it right.
\n" ); document.write( "\"9x%5E2-18x=-3\"
\n" ); document.write( "Divide each term by 9 to get x^2 term to have coefficient of 1:
\n" ); document.write( "\"x%5E2-2x=-1%2F3\"
\n" ); document.write( "Divide coefficient of x by 2 and square. add result to both sides:
\n" ); document.write( "\"x%5E2-2x%2B1=2%2F3\"
\n" ); document.write( "Represent left side as perfect square:
\n" ); document.write( "\"%28x-1%29%5E2=2%2F3\"
\n" ); document.write( "Take square root of each side:
\n" ); document.write( "x-1=+-sqrt(2/3)
\n" ); document.write( "Solve for x:
\n" ); document.write( "x=1+-sqrt(2/3)
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\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com
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