document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210394>Question 210394</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive odd integers such that 3 times the 2nd minus the 3rd is 31 more than the first.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159006 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive odd integers such that 3 times the 2nd minus the 3rd is 31 more than the first. <BR>\n" );
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document.write( "1st: 2x-1<BR>\n" );
document.write( "2nd: 2x+1<BR>\n" );
document.write( "3rd: 2x+3<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "3*(2x+1)-(2x+3) = (2x-1)+31<BR>\n" );
document.write( "------------------------------<BR>\n" );
document.write( "6x-3 - 2x-3 = 2x+30<BR>\n" );
document.write( "---<BR>\n" );
document.write( "4x-6 = 2x+30<BR>\n" );
document.write( "2x = 36<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "1st: 2x-1 = 35<BR>\n" );
document.write( "2nd: 2x+1 = 37<BR>\n" );
document.write( "3rd: 2x+3 = 39<BR>\n" );
document.write( "=================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );